F(x)=10x^2-6x-3

Solution for F(x)=10x^2-6x-3 equation:

(F)=10F^2-6F-3

We move all terms to the left:

(F)-(10F^2-6F-3)=0

We get rid of parentheses

-10F^2+F+6F+3=0

We add all the numbers together, and all the variables

-10F^2+7F+3=0

a = -10; b = 7; c = +3;
Δ = b2-4ac
Δ = 72-4·(-10)·3
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-13}{2*-10}=\frac{-20}{-20}
=1
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+13}{2*-10}=\frac{6}{-20}
=-3/10
$